Paper folding (origami) has been used by many teachers, particularly in Japan, to teach mathematics. In this post, we are going to use paper folding to locate the square root of any number on the number line. A GeoGebra simulation of the paper folding is shown below.

**Note **(July 17, 2014): Applet had an error. I will update it within 24 hours.

**Paper Folding Instructions **

- Get a rectangular piece of paper and fold it in the middle, horizontally and vertically, and let the creases (see green segments in the applet) represent the coordinate axes.
- Construct point
*M*at (0,1), and fold and make a crease at*y*= -1 (see blue segment above). - Let
*P*denote a point with coordinates (0,*n*) where*n*< 0 (drag*P*along the negative*y*-axis). - Make a fold through
*P*(by dragging*Q*in the applet) that places*M*(0,1) on the line*y*= – 1. - The
*x*intercept of the fold is .

**The Mathematics Behind**

**Theorem:**The

*x*intercept of the fold above is .

Before we proceed with the proof, in the applet check the

*Show/Hide Triangles*check box to display the triangles*MNO*and*OPN*. You can also uncheck the*Show/Hide Fold*check box to get a better view of the triangles.

**Proof:**

Let

*m*be*x*-intercept of the fold. It is clear that . This implies that.

But , , and . Subsituting the values, we have

.

Therefore and .

This means that for every value for , the intersection of the fold is always . In effect, using this method, we can locate the number or the length on the number line.

***

**Reference:**My old dilapidated geometry notebook, so I don’t really know to whom I shall attribute this. Our teacher in Geometry never used any reference. He could talk all day without looking at any book.