## Math Word Problems: Solving Number Problems Part 3

This is the third part of the Solving Number Problems Series. The first part can be read here and the second part can be read here.  In this post I will continue worked examples using problems which are slightly more complicated than the problems in the previous two parts. Without further ado, lets start with the seventh problem in the series.

PROBLEM 7

Twice a number added to $18$ is $5$ times that number. What is the number?

Solution

In the two previous posts, we have learned that if $n$ is a number, then twice that number is $2n$. So, twice a number added to $5$ is represented by $2n + 5$. Now, that number, the $2n + 5$ is five times that number of $5n$. So, we can now set up the equation $2n + 18 = 5n$.

If we solve for $n$, we have $n = 6$» Read more

## GeoGebra Institute of Manila’s New Site

The website of the GeoGebra Institute of Metro Manila (GIMM)  has been transferred here: http://geogebrainstituteph.blogspot.com/ We are still waiting for our official URL. Starting October 2012, we will be accepting post contributions from GeoGebra users in the Philippines. If you are interested, please contact me or email me at nismedmultimedia@gmail.com.

If I were you, I would immediately inform my employer that I can’t accept this paycheck since $e^{i\pi} = -1$ and $\sum_{n=1}^{\infty}\frac{1}{2^n}=1$ (Why?). This is only worth 0.002 dollars. 