A rhombus is a parallelogram with four congruent sides. Since it is a parallelogram, it has also all the properties of a parallelogram. One of these properties is that the diagonals bisect each other. That is, they divide each other into two equal parts.

Another property of a rhombus is that the **diagonals are perpendicular**. So, summarizing all the properties above, if we have rhombus , then,

.

and

.

From the figure below, it is clear that if we divide the parallelogram into two triangles, and , and are their altitudes because they are perpendicular to .

To find the area of parallelogram , first we find the area of triangle , and then multiply it by 2. This is because triangle is congruent to triangle by SSS congruence (can you see why?).

Now, we know that the area of a triangle is 1/2 the product of the base and the height, so

area of triangle .

But we also know that is half of , so

Area of .

Now, to get the area of ABCD, we multiply the area of ABC by 2. That is,

Area of parallelogram

This is what we want to prove: the area of parallelogram is half the product of diagonals and .