# Proof Without Words: If x >0, x + 1/x >=2

A picture is worth a thousand words, even in mathematics. Most of the time, complicated algebraic statements can be shown using geometric representations. One example is the sum of

$\frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \frac{1}{16} + \cdots$

In this post, we show another geometric proof without words. Proof without words is not a proof per se but rather a representation that will help readers understand the proof.

Theorem: If $x > 0$,  $x + \dfrac{1}{x} \geq 2$.

We can test a few examples. Since $x > 0$, we can test a few positive integers. Suppose $x = 1$, then

$x + \frac{1}{x} = 1 + \frac{1}{1} = 2$.

Now,

if $x = 2$, $x + \dfrac {1}{x} = 2 + \dfrac{1}{2}$

Notice that as $x$ increases, $x + \frac{1}{x}$ increases, so for $x > 1$,  $x + \frac{1}{x} > 2$.

We can also test numbers between 0 and 1. For example, $x = 0.5$, then

$0.5 + \frac{1}{0.5} = 0.1 + 2 = 2.5$.

Also, for x $x = 0.1$,

$0.1 + \frac{1}{0.1} = 0.1 + 10 = 10.1$.

As we can see, they are also greater than 2.

Instead of substituting x by individual values, we can also graph the function $f(x) = x + \frac{1}{x}$. As we can see in the graph below, the condition $x > 0$ represents the area of the Cartesian plane to the right of y-axis.

It is clear that the graph on that area is above the y-axis and all its parts is greater than or equal to 2. But again, this is not the proof since we cannot see all the parts of the graph.

The Proof

We can form rectangles of dimensions $x$ and $\frac{1}{x}$. The area of each of these rectangles is equal to $(x)(\frac{1}{x}) = 1$.

The area of the square is $(x + \frac{1}{x})^2$ which must be greater than or equal to 4. This is because it includes the area of the four green rectangles (4 square units) and the square of the square in the middle. Therefore, $x + \frac{1}{x}$ must be greater than or equal to 2. Therefore, $x + \frac{1}{x} \geq 2$.

Adapted Proofs without Words: Exercises in Visual Thinking by Roger B. Nelson