Math Word Problems: Solving Number Problems Part 3

This is the third part of the Solving Number Problems Series. The first part can be read here and the second part can be read here.  In this post I will continue worked examples using problems which are slightly more complicated than the problems in the previous two parts. Without further ado, lets start with the seventh problem in the series.


Twice a number added to 18 is 5 times that number. What is the number?


In the two previous posts, we have learned that if n is a number, then twice that number is 2n. So, twice a number added to 5 is represented by 2n + 5. Now, that number, the 2n + 5 is five times that number of 5n. So, we can now set up the equation

2n + 18 = 5n.

If we solve for n, we have n = 6» Read more