## Introduction to Age Problems in School Mathematics

Age Problems is the second part of the Math Word Problem Solving Series here in Mathematics and Multimedia. In this series, we are going to learn how to solve math word problems involving age.

Age problems are very similar to number word problems. They are easy to solve when you know how to set up the correct equations. Most of the time, this type of problem discusses the age of a certain individual in relation to another in the past, present, or future.

Below, are some of the common phrases used in age problems. In all the phrases, we let x be the age of Hannah now.

• Hannah’s age four years from now (x + 4)
• Hannah’s age three years ago (x – 3)
• Karen is twice as old as Anna (Karen’s age: 2x)
• Karen is thrice as old as Anna four years ago (Karen’s age: 2(x-4))

In solving age problems, creating a table is always helpful. This is one of the strategies that I am going to discuss in this series. As a start, we discuss one sample problem. » Read more

## Math Word Problems: Solving Age Problems Part 3

This is the third part of the Solving Age Problems of the Math Word Problem Solving Series. In this post, we discuss more complicated age word problems.

Problem 7

Anna who is $6$ years old and his father Ben who is $27$ years old have the same birthday. In how many years will Ben be twice as old as Anna?

Solution

As years go by, the number of years added to Ben’s and Anna’s ages is the same. If we let the number of years that have gone by be $x$, then in $x$ years, their ages will be

Ben’s Age: $27 + x$

Anna’s Age: $6 + x$

Since in $x$ years, Ben will be as twice as old as Anna, if we multiply Anna’s age by $2$, their ages will be equal. So, we can now set up the equation » Read more